Is it possible to output the numpad's pattern using loops?

Question

I just started learning C (coding in general) a few months ago. Earlier today when I was in class, I looked at the numpad and wondered whether I would be able to replicate the pattern using nested loops in C.

7 8 9
4 5 6
1 2 3 // This pattern.

I tried to do it myself for a bit, using for loops primarily. Thanks for any help.

#include<stdio.h>

int main()
{
    int row, col, i;

printf("Up to what integer? ");
scanf("%d", &row);

for(i=1; i<=row; i++)
{
    for(col=1; col<=10; col++)
    {
        printf(" %d ", i*col);
    }
    printf("\n");
    }
}

Edit: Added supplementary code. Something like this, except to print 3 rows and 3 columns.

Answer 1

The numpad pattern has the equation 3*i + j with i going from 2 to 0 and j going from 1 to 3.

So use these values as upper and lower limits of i and j in nested for loops.

#include <stdio.h>

int main(){

    for(int i = 2; i >= 0; i--){
        for(int j = 1; j <= 3; j++)
            printf("%d ", 3 * i + j);
        printf("\n");
    }
  return 0;
}

See it live here.