i need to dinamically generate expression like this:
Expression<Func<MyClass, bool>> expr = x => (x.SomeField.CompareTo(someValue) <= 0);
trying to do it like this:
var paramExpr = Expression.Parameter(typeof(MyClass), "x");
Expression<Func<MyClass, FieldType>> pathToField = x => x.SomeField;
Expression path = pathToField;
if (!(path is LambdaExpression lambdaMember))
throw ...;
Expression valueExpr = Expression.Constant(someValue);
var bodyExpr = Expression.LessThanOrEqual(Expression.Call(lambdaMember.Body, "CompareTo", null, valueExpr ), Expression.Constant(0));
return Expression.Lambda<Func<MyClass, FieldType>>(bodyExpr, paramExpr);
but always getting error when trying to compile this:
variable 'x' of type 'MyClass' referenced from scope '', but it is not defined
how i could do this correctly?
The problem here is that you're using lambdaMember.Body
, which references the x
from x => x.SomeField
- but because you only used the .Body
, that is undefined - and is unrelated to the x
from Expression.Parameter(typeof(MyClass), "x");
In the general case, there are 2 options here:
lambdaMember
, not lambdaMember.Body
) - passing in the arguments to use for the parametersExpressionVisitor
- swapping out instances of the x
from the inner expression with whatever you wanted to use as the argument - presumably paramExpr
The first option is easier, and is just Expression.Invoke
:
var bodyExpr = Expression.LessThanOrEqual(
Expression.Call(Expression.Invoke(lambdaMember, paramExpr),
"CompareTo", null, valueExpr), Expression.Constant(0));
Note: there is a third option in this case, since it is a relatively simple example - you can just hijack the parameter from the inner expression and use it instead of declaring paramExpr
as a new parameter expression:
var paramExpr = lambdaMember.Parameters.Single();
Expression valueExpr = Expression.Constant(someValue);
var bodyExpr = Expression.LessThanOrEqual(
Expression.Call(lambdaMember.Body,
"CompareTo", null, valueExpr), Expression.Constant(0));
return Expression.Lambda<Func<MyClass, FieldType>>(bodyExpr, lambdaMember.Parameters);