I am working through the Minimax algorithm with Alpha-Beta Pruning example found here. In the example, they use an array to implement the search tree. I followed the example, but also tried implementing it with a binary search tree as well. Here are the values I'm using in the tree: 3, 5, 6, 9, 1, 2, 0, -1.
The optimal value at the end should be 5. With the BST implementation, I keep getting 2.
I think this is the problem, but I don't know how to get around it:
I wrote the code to return out of recursion if it sees a leaf node to stop from getting null pointer exceptions when trying to check the next value. But instead, I think it's stopping the search too early (based off of what I see when stepping through the code with the debugger). If I remove the check though, the code fails on a null pointer.
Can someone point me in the right direction? What am I doing wrong?
Here's the code:
public class AlphaBetaMiniMax {
private static BinarySearchTree myTree = new BinarySearchTree();
static int MAX = 1000;
static int MIN = -1000;
static int opt;
public static void main(String[] args) {
//Start constructing the game
AlphaBetaMiniMax demo = new AlphaBetaMiniMax();
//3, 5, 6, 9, 1, 2, 0, -1
demo.myTree.insert(3);
demo.myTree.insert(5);
demo.myTree.insert(6);
demo.myTree.insert(9);
demo.myTree.insert(1);
demo.myTree.insert(2);
demo.myTree.insert(0);
demo.myTree.insert(-1);
//print the tree
System.out.println("Game Tree: ");
demo.myTree.printTree(demo.myTree.root);
//Print the results of the game
System.out.println("\nGame Results:");
//run the minimax algorithm with the following inputs
int optimalVal = demo.minimax(0, myTree.root, true, MAX, MIN);
System.out.println("Optimal Value: " + optimalVal);
}
/**
* @param alpha = 1000
* @param beta = -1000
* @param nodeIndex - the current node
* @param depth - the depth to search
* @param maximizingPlayer - the current player making a move
* @return - the best move for the current player
*/
public int minimax(int depth, MiniMaxNode nodeIndex, boolean maximizingPlayer, double alpha, double beta) {
//Base Case #1: Reached the bottom of the tree
if (depth == 2) {
return nodeIndex.getValue();
}
//Base Case #2: if reached a leaf node, return the value of the current node
if (nodeIndex.getLeft() == null && maximizingPlayer == false) {
return nodeIndex.getValue();
} else if (nodeIndex.getRight() == null && maximizingPlayer == true) {
return nodeIndex.getValue();
}
//Mini-Max Algorithm
if (maximizingPlayer) {
int best = MIN;
//Recur for left and right children
for (int i = 0; i < 2; i++) {
int val = minimax(depth + 1, nodeIndex.getLeft(), false, alpha, beta);
best = Math.max(best, val);
alpha = Math.max(alpha, best);
//Alpha Beta Pruning
if (beta <= alpha) {
break;
}
}
return best;
} else {
int best = MAX;
//Recur for left and right children
for (int i = 0; i < 2; i++) {
int val = minimax(depth + 1, nodeIndex.getRight(), true, alpha, beta);
best = Math.min(best, val);
beta = Math.min(beta, best);
//Alpha Beta Pruning
if (beta <= alpha) {
break;
}
}
return best;
}
}
}
Output:
Game Tree:
-1 ~ 0 ~ 1 ~ 2 ~ 3 ~ 5 ~ 6 ~ 9 ~
Game Results:
Optimal Value: 2
Your problem is your iterations are depending on a loop control of 2, and not a node == null finding for nodeIndex.getRight()(for max) getLeft(for min.)
Remember a tree has 1 head(first level)
2nd level = 2
3rd level = 4
4th 8 and so on. So your algorithm for looping will not even go down 3 levels.
for (int i = 0; i < 2; i++) {
int val = minimax(depth + 1, nodeIndex.getLeft(), false, alpha, beta);
best = Math.max(best, val);
alpha = Math.max(alpha, best);
//Alpha Beta Pruning
if (beta <= alpha) {
break;
}
Change your loops to control iteration correctly and you should find the highest value easily.