Execute HTTP requests in by-pass order

Question

What I would like to achieve is to execute synchronously an ordered sequence of HTTP requests, but depending on the value of some variables, I want some of them to be by-passed.

As an example (I am using the request library in Javascript to do so):

request(httpReq1, function(error, response, body) {
  // do something, like handling errors...
  request(httpReq2, function(error, response, body) {
    // do something else
  });
});

So this ensures that httpReq2 will execute after httpReq1.

What I am not sure is how to by-pass the first request if, for example, some flag is set to false, and instead of executing httpReq1 and wait for a response, it just jumps to httpReq2, keeping the order:

if (dontMakeHttpReq1) // where should this be placed?

request(httpReq1, function(error, response, body) {
  // do something, like handling errors...
  request(httpReq2, function(error, response, body) {
    // do something else
  });
});

What would be a good approach to solve this?

Answer 1

Sort out a list of requests needed in an array, and execute them sequentially using the async/await

let requests = [];
if (doRequest1)
  requests.push(httpReq1);

if (doRequest2)
  requests.push(httpReq2);

/* etc .. for httpReq3 and so on */

// now execute them one by one in sequence
for(let req of requests) {
   try {
     await request(req);
   } catch (err) {
     // error handling here
   }
}