I have a website with an ongoing webcam stream which should send snapshots of the video stream to my own Java webserver. The snapshot generating and displaying functionality works perfectly on the website. I want to send the snapshot with a jQuery AJAX POST request to my webserver which looks like that:
$.ajax({
type: 'POST',
url: servicePath + "upload",
contentType: 'multipart/form-data',
xhrFields: {withCredentials: false},
headers: {},
data: hidden_canvas.toDataURL('image/png'),
success: function(data, status, xhttp) {
alert(data);
},
error: function() {
alert("Error uploading snapshot file to server!");
}
});
As I mentioned, displaying the hidden_canvas.toDataURL('image/png')
inserted in a src
attribute of an <img>
works perfectly, so it is definitely valid.
My service on the webserver looks as follows:
@POST
@Path("/upload")
@Consumes(MediaType.MULTIPART_FORM_DATA)
public Response uploadPicture(byte[] imageBytes) {
String uploadedFileLocation = UPLOAD_FOLDER + "test.png";
try {
OutputStream out = new FileOutputStream(new File(uploadedFileLocation));
out.write(imageBytes);
out.flush();
out.close();
} catch (IOException e) {
return Response.status(500).entity("Can not save file<br>" + e.toString()).build();
}
return Response.status(200).entity("success").build();
}
Test.png
is created successfully but not a valid png
, when I open it, it does not display at all. And the file on the server looks as follows:
What did I miss? Would there be an alternative way to process the image?
Here's my takeSnapshot
method. How could I send the file without the toDataURL()
? And what for param would I have to expect then on the server side?
function generateSnapshot() {
var video = document.querySelector('#camera-stream');
var hidden_canvas = document.querySelector('#canvas');
var context = hidden_canvas.getContext('2d');
var width = video.videoWidth;
var height = video.videoHeight;
if (width && height) {
hidden_canvas.width = width;
hidden_canvas.height = height;
// Make a copy of the current frame in the video on the canvas.
context.drawImage(video, 0, 0, width, height);
// Turn the canvas image into a dataURL that can be used as a src for our photo.
return hidden_canvas.toDataURL('image/png');
}
}
I finally could make it work. The toBlob
suggestion from Kayaman put me on the right track. But I was not able to send the blob as expected, I had to put it into a FormData
and thus had to adjust my webservice. The solution looks as follows:
Website Javascript code:
hidden_canvas.toBlob(function(blob) {
var fd = new FormData();
fd.append('fileName', 'testBlob.png');
fd.append('data', blob);
sendAJAXFileUploadRequest(fd);
},'image/png');
function sendAJAXFileUploadRequest(formData) {
$.ajax({
type: 'POST',
url: servicePath + "upload",
xhrFields: {withCredentials: false},
headers: {},
data: formData,
processData: false,
contentType: false,
success: function(data, status, xhttp) {
alert(data);
},
error: function() {
alert("Error uploading snapshot file to server!");
}
});
}
And the Java Webservice:
@POST
@Path("/upload")
@Consumes(MediaType.MULTIPART_FORM_DATA)
public Response uploadPicture(@FormDataParam("data") byte[] imageBytes, @FormDataParam("fileName") String fileName) {
String uploadedFileLocation = UPLOAD_FOLDER + fileName;
try {
OutputStream out = new FileOutputStream(new File(uploadedFileLocation));
out.write(imageBytes);
out.flush();
out.close();
} catch (IOException e) {
logger.severe("Can not save file (file location: " + uploadedFileLocation + ")");
return Response.status(500).entity("Can not save file<br>" + e.toString()).build();
}
return Response.status(200).entity("success").build();
}