Encode and decode skipping the characters

Question

I am trying to store some strings into the database using their encoded format. But when retrieving back the string is malformed.

Here is my code example where you easily can see that String passed to encode is not the same as after decode. Why is this happening?

Is there any other library which can help me encoding and decoding? Any suggestion on the same will be helpful.

var Base64 = {
    _keyStr : "ABCDEFGHIJKLMNOPQRSTUVWXYZabcdefghijklmnopqrstuvwxyz0123456789+/=",
    encode : function(e) {
        var t = "";
        var n, r, i, s, o, u, a;
        var f = 0;
        e = Base64._utf8_encode(e);
        while (f < e.length) {
            n = e.charCodeAt(f++);
            r = e.charCodeAt(f++);
            i = e.charCodeAt(f++);
            s = n >> 2;
            o = (n & 3) << 4 | r >> 4;
            u = (r & 15) << 2 | i >> 6;
            a = i & 63;
            if (isNaN(r)) {
                u = a = 64
            } else if (isNaN(i)) {
                a = 64
            }
            t = t + this._keyStr.charAt(s) + this._keyStr.charAt(o)
                    + this._keyStr.charAt(u) + this._keyStr.charAt(a)
        }
        return t
    },
    decode : function(e) {
        var t = "";
        var n, r, i;
        var s, o, u, a;
        var f = 0;
        e = e.replace(/[^A-Za-z0-9+/=]/g, "");
        while (f < e.length) {
            s = this._keyStr.indexOf(e.charAt(f++));
            o = this._keyStr.indexOf(e.charAt(f++));
            u = this._keyStr.indexOf(e.charAt(f++));
            a = this._keyStr.indexOf(e.charAt(f++));
            n = s << 2 | o >> 4;
            r = (o & 15) << 4 | u >> 2;
            i = (u & 3) << 6 | a;
            t = t + String.fromCharCode(n);
            if (u != 64) {
                t = t + String.fromCharCode(r)
            }
            if (a != 64) {
                t = t + String.fromCharCode(i)
            }
        }
        t = Base64._utf8_decode(t);
        return t
    },
    _utf8_encode : function(e) {
        e = e.replace(/rn/g, "n");
        var t = "";
        for (var n = 0; n < e.length; n++) {
            var r = e.charCodeAt(n);
            if (r < 128) {
                t += String.fromCharCode(r)
            } else if (r > 127 && r < 2048) {
                t += String.fromCharCode(r >> 6 | 192);
                t += String.fromCharCode(r & 63 | 128)
            } else {
                t += String.fromCharCode(r >> 12 | 224);
                t += String.fromCharCode(r >> 6 & 63 | 128);
                t += String.fromCharCode(r & 63 | 128)
            }
        }
        return t
    },
    _utf8_decode : function(e) {
        var t = "";
        var n = 0;
        var r = c1 = c2 = 0;
        while (n < e.length) {
            r = e.charCodeAt(n);
            if (r < 128) {
                t += String.fromCharCode(r);
                n++
            } else if (r > 191 && r < 224) {
                c2 = e.charCodeAt(n + 1);
                t += String.fromCharCode((r & 31) << 6 | c2 & 63);
                n += 2
            } else {
                c2 = e.charCodeAt(n + 1);
                c3 = e.charCodeAt(n + 2);
                t += String.fromCharCode((r & 15) << 12 | (c2 & 63) << 6 | c3
                        & 63);
                n += 3
            }
        }
        return t
    }
}


var str = "background:url(/XYX/player_assets/skin_0/XYXA_default_skinRightCorner.png) ;"

var encoded = Base64.encode(str);
//console.log(encoded);

var decoded = Base64.decode(encoded);
console.log(str,"......Input");
console.log(decoded,".....Output");

Answer 1

Base64 Encoding in common browsers

In JavaScript there are two functions respectively for decoding and encoding base64 strings:

atob()

btoa()

The atob() function decodes a string of data which has been encoded using base-64 encoding. Conversely, the btoa() function creates a base-64 encoded ASCII string from a "string" of binary data.