#include <iostream>
struct A {
void test() { std::cout << "A\n"; }
};
struct B : A {
void test() { std::cout << "B\n"; }
};
struct C : B {
using A::test;
using B::test;
};
int main() {
C().test(); // Is this ambiguous?
return 0;
}
In this example, g++ 8.1.0 compiles successfully and calls test()
from B
.
clang++ 3.8.0 reports: error: call to member function 'test' is ambiguous
.
Which is correct? If it is g++, what is the rule that picks B::test
over A::test
?
I believe Clang is correct. According to [namespace.udecl]/13:
Since a using-declaration is a declaration, the restrictions on declarations of the same name in the same declarative region ([basic.scope]) also apply to using-declarations.
Since you can't declare two identical member functions, the same applies to using
declarations.