My Code:
models.py
from flask_mongoengine import MongoEngine, QuerySet
import datetime
db = MongoEngine()
class Service(db.Document):
service_name = db.StringField(max_length=50, required=True)
date_created = db.DateTimeField(default=datetime.datetime.utcnow)
meta = {
'ordering': ['-date_created'], 'strict' : False
}
class Organisation(db.Document):
org_name = db.StringField(max_length=50, required = True)
service = db.ReferenceField(Service, reverse_delete_rule='CASCADE', required=True)
date_created = db.DateTimeField(default=datetime.datetime.utcnow)
meta = {
'ordering': ['-date_created'], 'strict' : False
}
API(routes.py)
@service.route('/services/<name>', methods=['GET'])
def get_one_service(name):
s = Service.objects(service_name=name)
if s:
output = {'service_name' : s.service_name}
else:
output = "No such name"
return jsonify({'result' : output})
The get_one_service()
method returns the above mentioned error. As per the documentation, this is correct.
In your get_one_service
function, s
is not a Service
instance but a queryset (this example from the documentation might make it clearer)
You can access a single instance of Service
by doing something like:
try
s = Service.objects.get(service_name=name)
output = {'service_name' : s.service_name}
except Service.DoesNotExist:
output = 'no such name'
Though, since the service_name
field is not unique in your model, you may get a MultipleObjectsReturned
exception if there's two documents with the same service_name
.
Alternatively, you can see if s
contains multiple Service
s and act accordingly.