function largestNumber(n) {
let output = "";
var toInt = parseInt(output);
for (let i = 1; i <= n; i++){
output = output + "9";
}
return output;
};
I dont know exactly how to get this to return an integer. I keep getting null, or no output. I have tried
return output.toInt;
var toInt = output.parseInt();
var toInt = output.parseInt(output);
var toInt = output.parseInt("output");
var toInt = parseInt(output);
var toInt = parseInt(output,10);
and a few other various ideas that I dont remember by this point xD. the help is greatly appreciated!
EDIT
Thanks for the help guys I found the problem in my code was the
var toInt = parseInt(output);
needed to come after the loop and then call
return toInt;
However, Barmar (I hope I spelled your name right) has a much cleaner effective solution.
Your current code always attempts to parse an integer from output
, but you always initialize output
to an empty string right before the parse, so you get no int as a result.
You need to wait until output
has been built up to its final value before you use parseInt()
.
function largestNumber(n) {
let output = "";
for (let i = 1; i <= n; i++){
output = output + "9";
}
return parseInt(output);
}
console.log(largestNumber(5));
console.log(largestNumber(15));
But really, this can be done in a much simpler way based on what your logic is currently doing:
function largestNumber(n) {
return parseInt("9".repeat(n));
}
console.log(largestNumber(5));
console.log(largestNumber(15));