I'm trying to use 'fwrite' and make snd files. I want to make IIR Filter. I made a FIR Filter and i use the codes to IIR Filter. (of course, change coeffs) But I think 'fwrite' doesn't work. Because the result of IIR filter is only zero. I think I did some mistakes in my code.
Can you give me a hint? i'm totally in panic now.
When I check output[], it looks fine. It has group of integer, as i respect.
I don't know how to write it.
I know the code is so long and looks difficult.
But I have no idea so if you give me a hand, it would be pleasured. Thanks for reading.
#include <stdio.h>
#include <stdint.h>
#include <memory.h>
// Filter Code Definitions
#define MAX_INPUT_LEN 80
#define MAX_FLT_LEN 14
#define BUFFER_LEN (MAX_FLT_LEN - 1 + MAX_INPUT_LEN)
double insamp[BUFFER_LEN];
// IIR inititialization
void IirFloatInit(void)
{
memset(insamp, 0, sizeof(insamp));
}
// the IIR filter function
void IirFloat(double *coeffs, double *input, double *output, int length, int
filterLength)
{
double acc;
double *coeffp;
double *inputp;
int n;
int k;
// put the new samples at the high end of the buffer
memcpy(&insamp[filterLength - 1], input, length * sizeof(double));
for (n = 0; n < length; n++) {
coeffp = coeffs;
inputp = &insamp[filterLength - 1 + n];
acc = 0;
for (k = 0; k < filterLength; k++) {
acc += (*coeffp++) * (*inputp--);
}
output[n] = acc;
}
memmove(&insamp[0], &insamp[length], (filterLength - 1) * sizeof(double));
}
double coeffs[MAX_FLT_LEN];
void intToFloat(int16_t *input, double *output, int length)
{
int i;
for (i = 0; i < length; i++) {
output[i] = (double)input[i];
}
}
void floatToInt(double *input, int16_t *output, int length)
{
int i;
for (i = 0; i < length; i++)
{
input[i] += 0.5;
if (input[i] > 32767.0)
{
input[i] = 32767.0;
}
else if (input[i] < -32768.0)
{
input[i] = -32768.0;
}
output[i] = (int16_t)input[i];
}
}
// number of samples to read per loop
int main(void)
{
int size;
int16_t input[MAX_INPUT_LEN];
int16_t output[MAX_INPUT_LEN];
double floatInput[MAX_INPUT_LEN];
double floatOutput[MAX_INPUT_LEN];
double coeffs[MAX_FLT_LEN];
FILE *in_fid;
FILE *out_fid;
FILE *filter;
// open the input waveform file
in_fid = fopen("input.snd", "rb");
if (in_fid == 0) {
printf("couldn't open input.snd");
return;
}
// open the output waveform file
out_fid = fopen("outputFloatIIR.snd", "wb");
if (out_fid == 0) {
printf("couldn't open outputFloat.snd");
return;
}
filter = fopen("coeffs_iir.txt", "r");
if (filter == NULL) {
puts("couldn't open coeffs_iir.txt");
return;
}
for (int i = 0; i < MAX_FLT_LEN; i++) {
fscanf(filter, "%le", &coeffs[i]);
printf("%le \n", coeffs[i]);
}
IirFloatInit();
do {
size = fread(input, sizeof(int16_t), MAX_INPUT_LEN, in_fid);
intToFloat(input, floatInput, size);
IirFloat(coeffs, floatInput, floatOutput, size, MAX_FLT_LEN);
floatToInt(floatOutput, output, size);
fwrite(output, sizeof(int16_t), size, out_fid);
} while (size != 0);
fclose(in_fid);
fclose(out_fid);
fclose(filter);
getchar();
return 0;
}
Into the manual (man printf) I can read this:
eE The double argument is rounded and converted in the style [-]d.ddde+-dd where there is one digit before the decimal-point character and the number of digits after it is equal to the precision; if the precision is missing, it is taken as 6; if the precision is zero, no decimal-point character appears. An E conversion uses the letter
E' (rather than
e') to introduce the exponent. The exponent always contains at least two digits; if the value is zero, the exponent is 00.
Into your file where coefficients are stored, are into that format? If you use a debugger, what happen with the value read into fscanf?
I mean, probably the format is not the expected and because of that you get 0. Maybe you want to use fscanf(filter, "%lf", &coeffs[i]);
?
What is the value returned by fscanf? Into the manual (man fscanf) can be read this:
RETURN VALUES These functions return the number of input items assigned. This can be fewer than provided for, or even zero, in the event of a matching failure. Zero indicates that, although there was input available, no conversions were assigned; typically this is due to an invalid input character, such as an alphabetic character for a `%d' conversion. The value EOF is returned if an input failure occurs before any conver- sion such as an end-of-file occurs. If an error or end-of-file occurs after conversion has begun, the number of conversions which were successfully completed is returned.