JavaRMI creates a single ServerSocket when some object is Exported?

Question

I am new in Java and JavaRMI so a have some doubts about how its works, see below:

public interface Something implements Remote {...}

public SomeStub extends UnicastRemoteObject implements Something {...}

Every time when I create and bind (registry.rebind(...)) one object of SomeStub I am creating a new ServerSocket to listen calls only for this object?

Example:

registry.rebind("...", new obj1);
registry.rebind("...", new obj2);
registry.rebind("...", new obj3).

2) So if the question 1 is true, is better use just only one stub of this object and threads to avoid create lots of serversockets?

PS: I am using the default serversocket and socket factories provided by the JavaRMI.

Answer 1

Every time when I create and bind (registry.rebind(...)) one object of SomeStub I am creating a new ServerSocket to listen calls only for this object?

No. Every time you export a new remote object RMI attempts to do port sharing, and creates a new ServerSocket only if it doesn't already have one it can share with the new object.

Binding has nothing to do with it.

NB This is not a stub. It is a remote object, and it has its own stub created by RMI. Don't misuse standard naming. Call it something else.

So if the question 1 is true

It isn't.

is better use just only one stub of this object and threads to avoid create lots of serversockets

No.