Multiple Variable Conditions for If Statement in PowerShell

Thanks for the help in this, I think i have over complicated the below but the logic just isn't responding how my mind is telling it too.

Logic in Question:

$a = "One"
$b = "Two"
$c = "Three"
$d = "Four"

If( {$a -and $b} -ne {$c and $d} ) {
   Write-Host "Values are Different"
} Else {
   Write-Host "values are the same"
}

I want the If statement to run when $a and $b are different to $c and $d, If the are the same see below, I want it to output that the values are the same

$a = "One"
$b = "One"
$c = "One"
$d = "One"

Thanks in advance!

Solution

You can use Compare-Object to compare the value pairs as arrays:

if (Compare-Object $a, $b   $c, $d  -SyncWindow 0) {
  'different'
} else {
  'same'
}

Note that this is convenient, but relatively slow, which may matter in a loop with many iterations.

The Compare-Object cmdlet compares two arrays and by default returns information about their differences.
-SyncWindow 0 compares only directly corresponding array elements; in other words: $a must equal $c, and $b must equal $d; without -SyncWindow, the array elements would be compared in any order so that 1, 2 would be considered equal to 2, 1 for instance.
Using the Compare-Object call's result as a conditional implicitly coerces the result to a Boolean, and any nonempty result - indicating the presence of at least 1 difference - will evaluate to $True.

As for what you tried:

Use of { ... } in your conditional is not appropriate.
Expressions enclosed in { ... } are script blocks - pieces of code you can execute later, such as with & or .

Even if you used (...) instead to clarify operator precedence (-ne has higher precedence than
-and), your conditional wouldn't work as expected, however:

($a -and $b) -ne ($c -and $d) treats all variables as Booleans; in effect, given PowerShell's implicit to-Boolean conversion, you're comparing whether one value pair has at least one empty string to whether the other doesn't.