Is it possible to render an input field without id? I would like to disable it in the twig file.
I want that because I have a error "non-unique id" in the chrome console.
I have conducted research using the Symfony's documentation and I have found something that should work: "Customizing Form Output all in a Single File with Twig"
The block I want to replace is
{%- block widget_attributes -%}
This block is inside of the form_div_layout.twig.html
I put this inside of my_form.twig.html {% form_theme form _self %}
{% block form_row %}
{%- block widget_attributes -%}
id="{{ id }}" name="{{ full_name }}"
{%- if disabled %} disabled="disabled"{% endif -%}
{%- if required %} required="required"{% endif -%}
{%- for attrname, attrvalue in attr -%}
{{- " " -}}
{%- if attrname in ['placeholder', 'title'] -%}
{{- attrname }}="{{ translation_domain is same as(false) ? attrvalue : attrvalue|trans({}, translation_domain) }}"
{%- elseif attrvalue is same as(true) -%}
{{- attrname }}="{{ attrname }}"
{%- elseif attrvalue is not same as(false) -%}
{{- attrname }}="{{ attrvalue }}"
{%- endif -%}
{%- endfor -%}
{%- endblock widget_attributes -%}
{% endblock form_row %}
{{ form_start(form) }}
......
And I get the error:
"Variable "full_name" does not exist. "
I don't want to edit the form_div_layout.html.twig
I did it!
For now, I think I found the solution
{% form_theme form _self %}
{% block form_row %}
{% block input_widget %}
{% set id = random() %} {# Random number for the id #}
{{ block('form_widget') }}
{% endblock input_widget %}
{% endblock form_row %}
{{ form_row(form.my_form) }}
This is not the final solution because I want the "id" not to show in the input form.