Array.prototype.some not working with ternary operator

Question

Why do the following two snippets not return the same value?

[1,2,3,4].some((el) => {
    if (el === 4) {
        return true;
    }
    else {
        return false;
    }
});

--> returns true

[1,2,3,4].some((el) => {
    el === 4 ? true : false;
});

--> returns false

Answer 1

Try this. You are missing return.

var x=[1,2,3,4].some((el) => {
     return el === 4 ? true : false;
});
console.log(x);
//Or you can do this
var y=[1,2,3,4].some(el => el === 4);
console.log(y);