Creating a computed property with Entity Framework 6

Question

I am using Database First approach and I have created model from a database. Now I have a datagrid view in my Winforms app, that is bound to a binding source. And all that works fine (an appropriate data is shown in datagrid view). Now the problem is, how to add a computed property that consists of two values (already found in db) ? For an example:

Lets say that I have a table user (id, username, first_name, last_name, user_type) but I want to have different columns in my bound datagrid view, and I want to have these columns:

username, full name, type

where "full name" is what would I get with first_name + " " + last_name.

I guess I can't just modify a model class manually like this:

public string FullName
{
    get
    {
        return FirstName + " " + LastName;
    }
    protected set {}
}

because this class is generated automatically , and my code will be deleted each time a generate models from an existing database (when I make some change), so this is not the real option...

Answer 1

Actually, I solved this by using partial class functionality: I have created another file that contains another portion of my User model class (with my additional properties) and everything went just fine.

namespace User.Model
{
    public partial class User
    {
        public string FullName
        {
            get
            {
                return (this.firstName + " " + this.lastName;
            }
            protected set { }
        }
    }
}

Now when I generate model classes, this new file is not affected by EF. Also this new field is correctly shown by datagrid view...