I am working on Spring Boot 1.5.9 application, and I am generating a jar that contains a Spring Boot application, but that can also be imported as part of another project.
Therefore, I am using below config to generate 2 jars : the exec, and the regular lib ones.
<plugin>
<groupId>org.springframework.boot</groupId>
<artifactId>spring-boot-maven-plugin</artifactId>
<configuration>
<classifier>exec</classifier>
</configuration>
</plugin>
However, now that I have this, I am not able to run the application from my IDE (Intellij) anymore, as it's not finding the application.yml.
I am sure there's a trick, but I can't find anything.. Any idea ?
I ended up using Maven profiles :
<profiles>
<profile>
<id>makeRelease</id>
<build>
<plugins>
<plugin>
<groupId>org.springframework.boot</groupId>
<artifactId>spring-boot-maven-plugin</artifactId>
<configuration>
<classifier>exec</classifier>
</configuration>
</plugin>
</plugins>
</build>
</profile>
</profiles>
When I make the release, I am calling this profile (maven with argument -P makeRelease) so that it generates the 2 jars.
The rest of the time, the regular behavior applies.