I have time
string which represents a time in ISO8601 format.
The formula to format to a date: {{ time.strftime('%Y-%m-%d') }}
Current output:
time = 2018-01-23T08:11:58.000000
output: 2018-01-23
I want to divide it in 6 hours spans:
time = 2018-01-23T08:11:58.000000
output: 2018-01-23_1 // last "1" represents second span of 6 hours in 24 hours day (6-12)
What I need to add to my formula to achieve this?
Just divided hour
by 6
.
{{ time.strftime('%Y-%m-%d') }}_{{ time.strftime('%H')/6 }}
and got results:
2018-01-23_1 // for hours 6-12
2018-01-23_2 // for hours 12-18
No idea why couldn't think this simple logic earlier.