I'm trying to find out how to use arguments on nested items in my query using Absinthe.
What I try to accomplish is this:
{
users(order: ASC) {
id
email
clients(order: DESC) {
id
email
}
}
}
Here's my Schema and Type:
query do
@desc "Get all users"
field :users, list_of(:user) do
arg :order, type: :sort_order, default_value: :asc
resolve &Resolvers.users/2
end
end
@desc "A user"
object :user do
field :id, :id
field :email, :string
field :clients, list_of(:user)
end
And the resolver:
def users(_, args, _) do
args
|> Enum.reduce(User, fn
{:order, order}, query ->
query |> order_by({^order, :email})
end)
|> Repo.all |> Repo.preload([:clients])
end
So my question is how and where should I place the sorting argument for the clients? With the above example I get an error:
"message": "Unknown argument \"order\" on field \"clients\" of type \"User\"."
Put the argument under the clients
field:
object :user do
field :id, :id
field :email, :string
field :clients, list_of(:user) do
arg :order, type: :sort_order, default_value: :asc
resolve &Resolvers.clients/2
end
end
Then write a resolver to handle the sorting:
def clients(user, %{order: clients_order}, _) do
sorted_clients = user.clients # TODO sort those clients into the desired order
{:ok, sorted_clients}
end