Where clause on json data in Sql Server 2016

Question

I have a nvarchar(1000) field in my table and I am storing JSON data in that column.

eg :

 CONTENT_RULE_ID    CONTENT_RULE
 1                  {"EntityType":"Inquiry", "Values":[1,2]}
 2                  {"EntityType":"Inquiry", "Values":[1,3]}
 3                  {"EntityType":"Inquiry", "Values":[2,4]}
 4                  {"EntityType":"Inquiry", "Values":[5,6,1]}
 6                  {"EntityType":"Inquiry", "Values":[8,1]}
 8                  {"EntityType":"Inquiry", "Values":[10,12,11]}

from this how can I get all the CONTENT_RULE_ID which is having inquiry id 1 using JSON_QUERY in sql server

Answer 1

@Harisyam, could you please try following query

declare @val int = 1

;with cte as (
    select *
    from CONTENT_RULES
    cross apply openjson (CONTENT_RULE, '$')
), list as (
    select 
    CONTENT_RULE_ID, replace(replace([value],'[',''),']','') as [value]
    from cte 
    where CONTENT_RULE_ID in (
    select CONTENT_RULE_ID
    from cte 
    where [key] = 'EntityType' and [value] = 'Inquiry'
    ) 
    and [key] = 'Values'
)
select 
CONTENT_RULE_ID, s.value
from list
cross apply string_split([value],',') s
where s.value = @val

I used SQL string_split function to get inquiry values one by one

output is

A second query can be following one

select
    CONTENT_RULE_ID
from CONTENT_RULES
cross apply openjson (CONTENT_RULE, '$')
where replace(replace(value,'[',','),']',',') like '%,1,%'

And maybe the most complete SQL query which requires OpenJSON support is as follows

select
    content_rule_id,
    [value]
from Content as c
cross apply openjson(c.CONTENT_RULE, '$') with (
    EntityType nvarchar(100),
    [Values] nvarchar(max) as json
) as e
cross apply openjson([Values], '$') as v