Google Maps, scraping address

Question

I'm using cheerio to scrape the next html.

<div class="google-map-wrap " style="padding-bottom:50px;">
<div class="google-map"></div><style>.google-map{width: 100%; height: 420px;} 
.google-map img {max-width:none !important;}</style><script>jQuery(document).ready(function(){jQuery(".google-map").gmap3({marker:{address: "Periferico Sur 2020"},map:{options:{zoom: 14,}}});});

I tried the following options and they haven't worked.

Expected = "Periferico Sur 2020"

$('div.google-map-wrap div.google-map').text()

$('div.google-map-wrap div.google-map').html()

$('div.google-map-wrap div.google-map').css()

But not working the result should be the address.

Answer 1

As commented before, cheerio won't be able to do it. But request already has the html so we can use it to find the string with indexOf(). Example:

.html

<div class="google-map-wrap " style="padding-bottom:50px;">
<div class="google-map"></div><style>.google-map{width: 100%; height: 420px;} 
.google-map img {max-width:none !important;}</style>
<script>jQuery(document).ready(function(){jQuery(".google-map").gmap3({marker:{address: "Periferico Sur 2020"},map:{options:{zoom: 14,}}});});

.js

var readAddress = function(html){
 var idx1 = html.indexOf('{marker:{address: "');
 var idx2 = idx1 + '{marker:{address: "'.length;
 var idx3 = html.indexOf('"', idx2);

address = html.substring(idx2, idx3);
}

request(url, (err, res, data) => {
    readAddress(data);
 });