i know that when two variable have same address they gonna have the same value but in my case the var " a " have same address in child and parent process after fork .. but when i set a = 1 in child process the value of a in father process stay 5 ... why ? and thanks
#include <stdio.h>
#include <unistd.h>
#include <stdlib.h>
int a = 5;
int main(int argc, char const *argv[]) {
pid_t pid;
pid = fork();
if (pid == -1) {
printf("%s\n", " erreur while creating fils !");
} else if (pid == 0){
a = 1;
printf("%s %d\n", "child", a);
printf("%s %p\n", "child", &a);
return printf("child done\n");
} else {
wait(0);
printf("%s %d\n", "father", a);
printf("%s %p\n", "father", &a);
return printf("father done\n");
}
}
Parent and child processes have different address spaces after fork()
.
Even if you use global variable, it's copied. When you try to change it, its copy value is changed.
they still have the same memory address.. why ?
There is a disconnection between physical memory and the virtual address space of a process. It seems same memory addresses there, that's only the virtual address. For more, 4G address space and mapping