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javascriptalgorithmsubsetpermutationcombinatorics

Given an array, how to generate all combinations of subset size k?


So given input = [1, 2, 3] and k=2 this would return:

1 2
1 3
2 1
2 3
3 1
3 2

This is the closest to what I am looking for, but not quite: http://algorithms.tutorialhorizon.com/print-all-combinations-of-subset-of-size-k-from-given-array/

function subsetsOfSize(a, used, startIndex, currentSize, k) {
  if (currentSize === k) {
    for (var i = 0; i < a.length; i++) {
      if (used[i])
        console.log(a[i]);
    }
    console.log('-');
    return;
  }
    
  if (startIndex === a.length)
    return;
    
  used[startIndex] = true;
  subsetsOfSize(a, used, startIndex+1, currentSize+1, k);

  used[startIndex] = false;
  subsetsOfSize(a, used, startIndex+1, currentSize, k);
}

var input = [1,2,3];
subsetsOfSize(input, Array(input.length).fill(false), 0, 0, 2);

^ Missing results such as 2 1, 3 1, 3 2, etc.

Secondly, I am not sure if I am naming this problem correctly because solutions to "all combinations of subset of size k" do not give the expected answer.


Solution

  • A recursive solution to find k-subset permutations (in pseudo-code):

    kSubsetPermutations(partial, set, k) {
        for (each element in set) {
            if (k equals 1) {
                store partial + element
            }
            else {
                make copy of set
                remove element from copy of set
                recurse with (partial + element, copy of set, k - 1)
            }
        }
    }
    

    Here's a run-through for an example:

    input: [a,b,c,d,e]
    k: 3

    partial = [], set = [a,b,c,d,e], k = 3
        partial = [a], set = [b,c,d,e], k = 2
            partial = [a,b], set = [c,d,e], k = 1 -> [a,b,c], [a,b,d], [a,b,e]
            partial = [a,c], set = [b,d,e], k = 1 -> [a,c,b], [a,c,d], [a,c,e]
            partial = [a,d], set = [b,c,e], k = 1 -> [a,d,b], [a,d,c], [a,d,e]
            partial = [a,e], set = [b,c,d], k = 1 -> [a,e,b], [a,e,c], [a,e,d]
        partial = [b], set = [a,c,d,e], k = 2
            partial = [b,a], set = [c,d,e], k = 1 -> [b,a,c], [b,a,d], [b,a,e]
            partial = [b,c], set = [a,d,e], k = 1 -> [b,c,a], [b,c,d], [b,c,e]
            partial = [b,d], set = [a,c,e], k = 1 -> [b,d,a], [b,d,c], [b,d,e]
            partial = [b,e], set = [a,c,d], k = 1 -> [b,e,a], [b,e,c], [b,e,d]
        partial = [c], set = [a,b,d,e], k = 2
            partial = [c,a], set = [b,d,e], k = 1 -> [c,a,b], [c,a,d], [c,a,e]
            partial = [c,b], set = [a,d,e], k = 1 -> [c,b,a], [c,b,d], [c,b,e]
            partial = [c,d], set = [a,b,e], k = 1 -> [c,d,a], [c,d,b], [c,d,e]
            partial = [c,e], set = [a,b,d], k = 1 -> [c,e,a], [c,e,b], [c,e,d]
        partial = [d], set = [a,b,c,e], k = 2
            partial = [d,a], set = [b,c,e], k = 1 -> [d,a,b], [d,a,c], [d,a,e]
            partial = [d,b], set = [a,c,e], k = 1 -> [d,b,a], [d,b,c], [d,b,e]
            partial = [d,c], set = [a,b,e], k = 1 -> [d,c,a], [d,c,b], [d,c,e]
            partial = [d,e], set = [a,b,c], k = 1 -> [d,e,a], [d,e,b], [d,e,c]
        partial = [e], set = [a,b,c,d], k = 2
            partial = [e,a], set = [b,c,d], k = 1 -> [e,a,b], [e,a,c], [e,a,d]
            partial = [e,b], set = [a,c,d], k = 1 -> [e,b,a], [e,b,c], [e,b,d]
            partial = [e,c], set = [a,b,d], k = 1 -> [e,c,a], [e,c,b], [e,c,d]
            partial = [e,d], set = [a,b,c], k = 1 -> [e,d,a], [e,d,b], [e,d,c]
    

    function kSubsetPermutations(set, k, partial) {
        if (!partial) partial = [];                 // set default value on first call
        for (var element in set) {
            if (k > 1) {
                var set_copy = set.slice();         // slice() creates copy of array
                set_copy.splice(element, 1);        // splice() removes element from array
                kSubsetPermutations(set_copy, k - 1, partial.concat([set[element]]));
            }                                       // a.concat(b) appends b to copy of a
            else document.write("[" + partial.concat([set[element]]) + "] ");
        }
    }
    kSubsetPermutations([1,2,3,4,5], 3);