I need general explanation of the code:
Case1)
In this factorial function, if num
is 0, then does it return 0!, which is 1?
Case2)
if number is >= than 1, it return fact
, which is it's factorial value?
I understand that return 1
and return 0
is both for successful generation of result.
Then why can't I do return 0, in this case?
double factorial(int num)
{
int fact = 1;
int i = 1;
if (num == 0)
return 1;
else
while (num >= i)
{
fact = fact*i;
i++;
}
return fact;
#include <iostream>
using namespace std;
int factorial(int num) //I changed this to return int since you are taking int and int*int will always be int
{
int fact = 1;
//int i = 1; //dont need this
if (num == 0)
return fact; //You can just say return `fact` or `return 1` - i like to make my code readable - s I used `return fact`
//I also prefer to set the value of fact as 1 here and return the 1 at bottom so we only have one return statement
//but thats just me - having 2 return statements should be fine if used wisely
/*while (num >= i) //thispart was wrong i reedited it into a better and more efficient code below
{
fact = fact*i;
i++;
}*/
else
{
while(num>1) // so lets say we enter 4 - 4 is larger than 1
{
fact*=num; //first step through it will be fact = fact * num; fact is 1 at first loop so it will be 1 * 4 and we put that value into fact
num--; //here we set num to 3 for next loop and we repeat :D
}
}
return fact; //here we return the value
}
int main() //just a normal main
{
int number;
cout<<"Enter number: \n";
cin>>number;
cout<<"Factorial of "<<number<<" is "<<factorial(number);
return 0;
}
I think your question was perfectly fine and being a beginner programmer myself it also helps me when I see questions like this. Hope this helps! Goodluck!