Is there a way to test if a value is in a list? In Python, I think you can do something like 'if n in myList: print("Value N is in the list.")'
I don't want to use a for loop to check each value seperately, unless it's the only option. I'm using a Ti-84 Plus.
This should work assuming I've thought through it correctly. It's very simple, where L₁
is the list to search and X
is the value to look for.
max(not(L₁-X
Step-by-step analysis:
L₁-X
: Subtract the value from everything in the list. Now, if this list contains a zero, it means our value was in L₁
.not(L₁-X
: Invert everything in the list. This converts all zeroes to ones, and everything else to zeroes. Now, if this list contains a one, it means our value was in L₁
. If the list is all zeroes, it was not.max(not(L₁-X
: Get the maximum value in the list. As stated above, the list will be all zeroes if the value was not inside L₁
, so the maximum value will be zero. If L₁
had the value inside, the maximum will be a one.This makes a check as simple as this:
If max(not(L₁-X
Disp "The value was found:",X