Trying to use an assert command in conjuntion with arraylist using selenium, but it breaks if the elements are not in the proper order

Question

I have a string that needs to be compared to the names that are on the website. So the first thing I do is get the number of rows (because some arrays have more or fewer than 2 people in them) and then put that size into an int. String[] names come from the names that selenium is supposed to find when it goes to the website to execute this statement assertTrue(assertion.getText().contains(names[i-1])); The problem is: if the names do not appear in the order in which they appear in the array it breaks. In other words, if Mick Jagger is in li[1] and Keith Richards is in li[2], everything runs as expected. But if Keith Richards appears in li[1] it breaks. Furthermore, I am supposed to use the assertTrue command to do this. I have tried sorting, pushing whats on the web into a new ArrayList and I keep getting errors. Anyone know a good way to ensure the order isn't important and still use the assertTrue command?

Thanks, Scott

    WebElement assertion = null;
    List<WebElement> assignees = driver.findElements(By.xpath(".//*[@id='assignee']/li"));
    int count = assignees.size();
    String[] names = {"Mick", "Keith"};
    for (int i = 1; i < count; i++)
    {
    assertion = driver.findElement(By.xpath(".//*[@id='assignee']/li["+i+"]"));

    assertTrue(assertion.getText().contains(names[i-1]));

Answer 1

If names represents the full string, you can just flip it. Make sure the text in your assertion (probably should be named something like assignee instead of assertion) is contained in your collection:

assertTrue(Arrays.asList(names).contains(assertion.getText());

Let me know if this won't work because a name is actually a subset of the text in assertion and I'll adjust the answer.

---

If they don't exactly match (which you have indicated they don't), you could use linq in c# to match this. Since you're using java you can use an additional loop. There may be a more efficient way to do this in java that I'm not aware of.

String assigneeText = assertion.getText();
boolean nameFound = false;
for(String name: names)
{
    nameFound = assigneeText.contains(name);

    if(nameFound)
    {
        break;
    }
}

assertTrue(nameFound, "None of the expected names were found in the following assignee text: " + assigneeText);