Groovy: Find and replace all node names

Question

Considering I have the following XML structure:

<Header>
   <Parent1>
       <Line> ABC </Line>
   </Parent1>
   <Parent1>
       <Line> CDE </Line>
   </Parent1>
   <Parent2>
       <Line> EFG </Line>
   </Parent2>
</Header>

I would want all Parent1 parent nodes to be changed to Parent2. Like so:

<Header>
   <Parent2>
       <Line> ABC </Line>
   </Parent2>
   <Parent2>
       <Line> CDE </Line>
   </Parent2>
   <Parent2>
       <Line> EFG </Line>
   </Parent2>
</Header>

Is there a simple way to do this requirement in Groovy?

Answer 1

You can use XmlSlurper to do this.

def xml = '''<?xml version='1.0' encoding='utf-8'?>
<Header>
   <Parent1>
       <Line> ABC </Line>
   </Parent1>
   <Parent1>
       <Line> CDE </Line>
   </Parent1>
   <Parent2>
       <Line> EFG </Line>
   </Parent2>
</Header>
'''

def result = new XmlSlurper().parseText(xml)

result.Parent1.replaceNode {
    'Parent2'(it.attributes(), it.children())
}

println(XmlUtil.serialize(result))

You can find more information in XML Processing documentation.