Windows batch file - replace a string in an XML file

Question

I have the following XML file: input.xml

<?xml version="1.0"?>
<configuration>
    <startup>
        <supportedRuntime version="v2.0.50727"/>
    </startup>
    <appSettings>
        <add key="Name1" value="Value1"/>
        <add key="Name2" value="Value2"/>
        <add key="Name3" value="Value3"/>
    </appSettings>
    <runtime>
        <legacyUnhandledExceptionPolicy enabled="true"/>
    </runtime>
</configuration>

I need to replace Value2 with ServerName using Windows Batch file programming.

Could anybody help one as I am new to Windows Batch programming?

Answer 1

Batch will have trouble with <, >, ^ and & characters. This will work, but a JScript/VBScript script (like is referenced in one of the comments) is a much better solution.

Change "ORIGINAL" to the text being searched for, and "REPLACE" to the new text. I recommend for Windows scripting to learn JScript.

@echo off
for /f "tokens=* delims=" %%f in ('type sometext.txt') do CALL :DOREPLACE "%%f"

GOTO :EOF
:DOREPLACE
SET INPUT=%*
SET OUTPUT=%INPUT:ORIGINAL=REPLACE%

for /f "tokens=* delims=" %%g in ('ECHO %OUTPUT%') do ECHO %%~g>>out.txt

EXIT /b

:EOF