I have a jquery document ready function of containing a fancy box for which I provide an html to render and I need to submit that form from fancy box and take it to the controller class of spring.
Whenever a Checkbox is checked, A fancy box appears, codes below
Here is my jquery fancy box code
$("input:checkbox")
.click(
function () {
if ($(this).is(':checked')) {
var htmlStr = '<div class="form"><form:form method="POST" action="mapping">' +
'<label> Map the Selected field to Category ? </label>'
+
'<select name="category" id="category">' +
'<option>COMPANY NAME</option>' +
'<option>LINE OF BUSINESS 1</option>' +
'</select>'
+
'<input type="button" name="mapBtn" id="mapBtn" value="MAP" class="ui-button ui-widget ui-corner-all"' +
'</form:form></div>';
$.fancybox
.open(
htmlStr, {
'width': 950,
'height': 1100,
'autoScale': false,
'transitionIn': 'none',
'transitionOut': 'none',
'hideOnContentClick': false
});
}
});
controller code is below
@PostMapping("mapping")
public String mapCategory()throws Exception{
try {
System.out.println("Welcome to mapping funcion");
} catch (Exception e) {
throw e;
}
return "viewUploadedExcel";
}
Since I am new to both the areas I explore it here. Help is appreciated. Thanks
You can make an Ajax POST Request to your Controller.
$( "#formButton" ).click(function() {
sendForm();
});
function sendForm(){
var data = $("#form").serializeArray();
$.ajax({
url: "http://localhost/mapping",
data: data
}).done(function(responseData) {
console.log(responseData)
});
}