I need to convert 8byte-long hex numbers to floating point in C#. For example :
4030000000000000 should be 16.0
C0622EB860000000 should be -14.46
4090000000000000 should be 1024.0
I have found this code that seems to work, but it doesn't place the point correctly for numbers larger than 10 and smaller than -10. For exemple, -14.46 is displayed as -1.4546. What is wrong with the code?
const string formatter = "{0,20}{1,27:E16}";
// Reinterpret the long argument as a double.
public static void LongBitsToDouble( long argument )
{
double doubleValue;
doubleValue = BitConverter.Int64BitsToDouble( argument );
// Display the argument in hexadecimal.
Console.WriteLine( formatter, String.Format( "0x{0:X16}", argument ),
doubleValue );
}
public static void Main( )
{
Console.WriteLine("This example of the BitConverter.Int64BitsToDouble( "
+"long ) \nmethod generates the following output.\n" );
Console.WriteLine( formatter, "long argument","double value" );
Console.WriteLine( "-------------" );
// Convert long values and display the results.
LongBitsToDouble( unchecked( (long)0x4030000000000000 )); //16.0
LongBitsToDouble( unchecked( (long)0xC0622EB860000000 )); //-14.46
Console.ReadKey();
}
Try following, 2nd number decimal place is wrong. I reversed the bytes. :
using System;
using System.Collections.Generic;
using System.Linq;
using System.Text;
namespace ConsoleApplication1
{
class Program
{
static void Main(string[] args)
{
List<List<byte>> inputs = new List<List<byte>>() {
new List<byte>() {0x40, 0x30, 0x00, 0x00, 0x00, 0x00, 0x00, 0x00},
new List<byte>() {0xC0, 0x62, 0x2E, 0xB8, 0x60, 0x00, 0x00, 0x00},
new List<byte>() {0x40, 0x90, 0x00, 0x00, 0x00, 0x00, 0x00, 0x00},
};
foreach (List<byte> input in inputs)
{
input.Reverse();
Console.WriteLine(BitConverter.ToDouble(input.ToArray(),0));
}
Console.ReadLine();
}
}
}