I am using NOTY (notification library) version 3.0.0 to show notification popups from JavaScript.
While having multiple notifications on the screen, when I click the close button, it always closes the last notification placed on screen. I know this is because the variable n is always overwritten by the last notification object in the sample code. But, I didn't find any clue in the documentation about how to handle notification close in case of multiple notifications.
Should I create an array of notification objects and then calling the .close() function like this n[i].close(), or do we have any better way to achieve this? Help please.
Sample code:
var n = new Noty({
type: 'success',
layout: 'bottomRight',
theme: 'relax',
text: "<b>Testing 2<br/><br/> ",
timeout: false,
closeWith: ['button'],
animation: {
open: 'noty_effects_open',
close: 'noty_effects_close'
},
buttons: [
Noty.button('CLOSE', 'btn btn-error', function () {
console.log('button 2 clicked');
n.close();
})
],
}).show();
I think you can use the queue
functionality where in you can push multiple objects to a queue variable and can manipulate those using below examples
Noty.closeAll(); // Closes all notifications
Noty.closeAll('myCustomQueueName'); // Closes all notifications with queue named 'myCustomQueueName'
Noty.setMaxVisible(10); // Sets the maxVisible notification count for global queue;
Noty.setMaxVisible(10, 'myCustomQueueName'); // Sets the maxVisible notification count for 'myCustomQueueName' queue;