I've seen few implementations of variations of string in C#, but none of them had any limitation on their length. Unfortunately, I cannot modify them to achieve my goal which is e.g.
for:
string = "ABCD" and variationLength = 2
generate new strings:
AB, AC, AD, BA, BC, BD, CA, CB, CD, DA, DB, DC
I'm looking for exactly this Python's itertools.permutations implementation but in C#. (https://docs.python.org/3/library/itertools.html#itertools.permutations)
Is there anything similar to its in C#? If not, then what is the easiest way to implement it?
Edit_2: so far I came up with an idea to list all unique chars of given string and then get variations out of them
static void PrintAllKLengthPerm(string str, int k)
{
int n = str.Length;
PrintAllKLengthPermRec(str, "", n, k);
}
// The main recursive method to print all possible strings of length k
static void PrintAllKLengthPermRec(string str, String prefix, int n, int k)
{
// Base case: k is 0, print prefix
if (k == 0)
{
Console.WriteLine(prefix);
return;
}
// One by one add all characters from str and recursively
// call for k equals to k-1
for (int i = 0; i < n; ++i)
{
// Next character of input added
String newPrefix = prefix + str[i];
// k is decreased, because we have added a new character
PrintAllKLengthPermRec(str, newPrefix, n, k - 1);
}
}
static void Main(string[] args)
{
string str = "ABCD";
int permLen = 2;
//get all unique characters in string
string uniqStr = new String(str.Distinct().ToArray());
// Print all possible strings of length permLen out of uniqStr characters
PrintAllKLengthPerm(uniqStr, permLen);
}
However I am looking for more optimal and effective solution
Here's a truly recursive permutation method:
public IEnumerable<string> Permutate(string source, int count)
{
if (source.Length == 1)
{
yield return source;
}
else if (count == 1)
{
for (var n = 0; n < source.Length; n++)
{
yield return source.Substring(n, 1);
}
}
else
{
for (var n = 0; n < source.Length; n++)
foreach (var suffix in Permutate(
source.Substring(0, n)
+ source.Substring(n + 1, source.Length - n - 1), count -1))
{
yield return source.Substring(n, 1) + suffix;
}
}
}
It can be called with Permutate("ABCD", 2)
and returns this: