First of all, here is the assembler code:
/ 0x000006a0 55 push rbp
| 0x000006a1 4889e5 mov rbp, rsp
| 0x000006a4 4883ec10 sub rsp, 0x10
| 0x000006a8 488d05b50000. lea rax, str.AAAA ; 0x764
| 0x000006af 488945f8 mov qword [local_8h], rax
| 0x000006b3 488b45f8 mov rax, qword [local_8h]
| 0x000006b7 4889c6 mov rsi, rax
| 0x000006ba 488d3da80000. lea rdi, 0x00000769 ; "%s"
| 0x000006c1 b800000000 mov eax, 0
| 0x000006c6 e895feffff call sym.imp.printf ;[2] ; i
| 0x000006cb b800000000 mov eax, 0
| 0x000006d0 c9 leave
\ 0x000006d1 c3 ret
to this c program:
#include <stdio.h>
#include <string.h>
int main(){
char* a = "AAAA";
printf("%s", a);
return 0;
}
Especially I have a question to this code snipped:
| 0x000006af 488945f8 mov qword [local_8h], rax
| 0x000006b3 488b45f8 mov rax, qword [local_8h]
What is the sense of these two instructions? I only see the same instruction one way and than reversed. But why is that?
Here are some further information to the executable:
blksz 0x0
block 0x100
fd 6
file demo
format elf64
iorw false
mode -r--
size 0x20e0
humansz 8.2K
type DYN (Shared object file)
arch x86
binsz 6559
bintype elf
bits 64
canary false
class ELF64
crypto false
endian little
havecode true
intrp /lib64/ld-linux-x86-64.so.2
lang c
linenum true
lsyms true
machine AMD x86-64 architecture
maxopsz 16
minopsz 1
nx true
os linux
pcalign 0
pic true
relocs true
relro partial relro
rpath NONE
static false
stripped false
subsys linux
va true
The lines are seperate from each other:
The first line belongs to the line char* a = "AAAA";
, saving the value of the variable to RAM.
The second line accesses the variable from RAM for the line printf("%s", a);
as the parameter.
Technically, both lines would be optional, as you could have written:
printf("%s", "AAAA");
EDIT: For skipping this unnecessary code, you could enable automatic optimizations (for GCC: -O2)