function composition with rest operator, reducer and mapper

Question

I'm following an article about Transducers in JavaScript, and in particular I have defined the following functions

const reducer = (acc, val) => acc.concat([val]);
const reduceWith = (reducer, seed, iterable) => {
  let accumulation = seed;

  for (const value of iterable) {
    accumulation = reducer(accumulation, value);
  }

  return accumulation;
}
const map =
  fn =>
    reducer =>
      (acc, val) => reducer(acc, fn(val));
const sumOf = (acc, val) => acc + val;
const power =
  (base, exponent) => Math.pow(base, exponent);
const squares = map(x => power(x, 2));
const one2ten = [1, 2, 3, 4, 5, 6, 7, 8, 9, 10];
res1 = reduceWith(squares(sumOf), 0, one2ten);
const divtwo = map(x => x / 2);

Now I want to define a composition operator

const more = (f, g) => (...args) => f(g(...args));

and I see that it is working in the following cases

res2 = reduceWith(more(squares,divtwo)(sumOf), 0, one2ten);
res3 = reduceWith(more(divtwo,squares)(sumOf), 0, one2ten);

which are equivalent to

res2 = reduceWith(squares(divtwo(sumOf)), 0, one2ten);
res3 = reduceWith(divtwo(squares(sumOf)), 0, one2ten);

The whole script is online.

I don't understand why I can't concatenate also the last function (sumOf) with the composition operator (more). Ideally I'd like to write

res2 = reduceWith(more(squares,divtwo,sumOf), 0, one2ten);
res3 = reduceWith(more(divtwo,squares,sumOf), 0, one2ten);

but it doesn't work.

Edit

It is clear that my initial attempt was wrong, but even if I define the composition as

const compose = (...fns) => x => fns.reduceRight((v, fn) => fn(v), x);

I still can't replace compose(divtwo,squares)(sumOf) with compose(divtwo,squares,sumOf)

Answer 1

Finally I've found a way to implement the composition that seems to work fine

const more = (f, ...g) => {
  if (g.length === 0) return f;
  if (g.length === 1) return f(g[0]);
  return f(more(...g));
}

Better solution

Here it is another solution with a reducer and no recursion

const compose = (...fns) => (...x) => fns.reduceRight((v, fn) => fn(v), ...x);
const more = (...args) => compose(...args)();

usage:

res2 = reduceWith(more(squares,divtwo,sumOf), 0, one2ten);
res3 = reduceWith(more(divtwo,squares,sumOf), 0, one2ten);

full script online