Printing a char array

Question

I am wondering what is wrong with my code. I normally use scanf but am trying get the hang of fgets. But when I try to print a char array where each element of the array is on a separate line, but even though I defined the limit of the array as an arbitrarily high number, it only has a limit of eleven lines. I am a beginner programmer so try to be as simple as you can.

#include <stdio.h> 
#define max_line 4096
int main(void) {
    char str[max_line];
    printf("Enter string: ");
    fgets(str, max_line, stdin);
    for (int i=0;i <max_line && i!='\n'; i++) {
        printf("%c\n", str[i]);
    }
    return 0;
}

I am wanting to get a result like this.

Enter string: Hello 
H
e
l
l
o

But it turns out quite differently

Enter string: Hello 
H
e
l
l
o 
/n //Sorry, I don't know how to add new lines in stackoverflow, but I think you get the idea.
/n
/n
/n
/n

Answer 1

You need to check that str[i] is NOT EQUAL to '\n' instead of checking i!='\n'. As @BLUEPIXY pointed out it means i != 10, being '\n' equal to 10 in the ASCII code.

So change the condition to:

for (int i=0;i <max_line && str[i]!='\n'; i++) {