Checking for palindrome using recursion in PYTHON

Question

I am checking if a word is a palindrome, and I cant seem to get my code to respond. I feel like its pretty sound, but apparently I'm missing something. can someone point out what that may be?

def reverse(usrWrd, index):   
    newWord = ""  

    if index == len(usrWrd):
        return newWord
    else:
      newWord += usrWrd[index]
      return reverse(usrWrd, index + 1)

def main(): 
    usrWrd = input("please enter a word to check for palindrome-ness:")

    result = reverse(usrWrd, 0)
    if result == usrWrd:
        print("That word is a palindrome")
    else:
        print("Sorry,",usrWrd,  "is NOT a palindrome")

main()

Answer 1

# Correct approach to your solution
def reverse(usrWrd, index, newWord):
    if index < 0:
        return newWord
    else:
      newWord += usrWrd[index]
      return reverse(usrWrd, index - 1, newWord)

def main():
    newWord = ""
    usrWrd = input("please enter a word to check for palindrome-ness:")
    result = reverse(usrWrd, len(usrWrd) - 1, newWord)

    if result == usrWrd:
        print("That word is a palindrome")
    else:
        print("Sorry,",usrWrd,  "is NOT a palindrome")

#############################################################

# Alternate approach
def isPalindrome(usrWord):
    sLen = len(usrWord)
    if sLen <= 1:
        return True
    else:
        if usrWord[0] != usrWord[sLen-1]:
            return False
        else:
            return isPalindrome(usrWord[1:sLen-1])

def main():
    newWord = ""
    usrWrd = input("please enter a word to check for palindrome-ness:")
    result = isPalindrome(usrWrd)

    if result:
        print("That word is a palindrome")
    else:
        print("Sorry,",usrWrd,  "is NOT a palindrome")

#############################################################

# Pythonic way as suggested by 'Yaman Jain'
if usrWord == usrWord[::-1]:
    return True # Palindrome
else:
    return False # Not Palindrome