I have read a csv file
input <- read.csv("abc.csv",header=FALSE)
and the data frame looks like..
i want my expected result like this.. in the timeStamp column i want to replace "2017/03/10 08:35:07.996" to only "08:35:07.996".
Tried a lot but could find any solution.Please help
We can set the digits.secs
to 3, then convert the 'timeStamp' to DateTime class with strptime
and format
it
op <- options(digits.secs=3)
input$timeStamp <- format(strptime(input$timeStamp, "%Y/%m/%d %H:%M:%OS"), "%H:%M:%OS")
Though, it is better not to use regex on timestamps, one way is to match one or more non-white space (\\S+
) character followed by one or more white space (\\s+
) from the start (^
) of the string and replace it with blanks (""
) so that the rest of the string i.e. time part remains
input$timeStamp <- sub("^\\S+\\s+", "", input$timeStamp)