Jersey rest api com.sun.jersey.api.container.ContainerExceptionServlet

Question

I am new to creating API's. I found what I thought was a simple example online but was unable to get it to work. Any help or advice would be great.

This is my web.xml file

<web-app xmlns="http://java.sun.com/xml/ns/j2ee"
xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
xsi:schemaLocation="http://java.sun.com/xml/ns/j2ee http://java.sun.com/xml/ns/j2ee/web-app_2_4.xsd"
version="2.4">

<display-name>Hello, World Application</display-name>
<description>
This is a simple web application with a source code organization
based on the recommendations of the Application Developer's Guide.
</description>

<servlet>
    <servlet-name>GetEDPInfo</servlet-name>
    <servlet-class>com.sun.jersey.spi.container.servlet.ServletContainer</servlet-class>
    <init-param>
        <param-name>com.sun.jersey.config.property.packages</param-name>
        <param-value>mypackage</param-value>
    </init-param>
    <load-on-startup>1</load-on-startup>
</servlet>

<servlet-mapping>
    <servlet-name>GetEDPInfo</servlet-name>
    <url-pattern>/GetEDPInfo</url-pattern>
</servlet-mapping>

This is my java example GetEDPInfo.java

package mypackage;

import javax.ws.rs.GET;
import javax.ws.rs.Path;
import javax.ws.rs.PathParam;
import javax.ws.rs.core.Response;

@Path("/GetEDPInfo")
public class GetEDPInfo {

@GET
@Path("/{param}")
public Response getMsg(@PathParam("param") String msg) {
String output = "Welcome"+ msg;
return Response.status(200).entity(output).build();
}

}

I downloaded these jar files and placed them in my WEB-INF/lib directory asm-3.1.jar, jersey-core-1.8.jar, jersey-server-1.8.jar not sure if I need more than that, but those were all the ones used on the example i looked at.

I compiled my java file with the following command: javac -source 1.7 -target 1.7 -bootclasspath /usr/java/jdk1.7.0_80/jre/lib/rt.jar cp .:/var/lib/tomcat6/webapps/sample/WEB-INF/lib/jersey-core-1.8:/var/lib/tomcat6/webapps/sample/WEB-INF/lib/jersey-server-1.8:/var/lib/tomcat6/webapps/sample/WEB-INF/lib/asm-3.1 GetEDPInfo.java

That created my class file with no errors.

When i navigate to http://grv4:8080/sample/GetEDPInfo i get this message...

HTTP Status 405 - Method Not Allowed

type Status report

message Method Not Allowed

description The specified HTTP method is not allowed for the requested resource (Method Not Allowed).

When I navigate to http://grv4:8080/sample/GetEDPInfo/Jeeves i get this message...

HTTP Status 404 - /sample/GetEDPInfo/Jeeves

type Status report

message /sample/GetEDPInfo/Jeeves

description The requested resource (/sample/GetEDPInfo/Jeeves) is not available.

This is my modified code...

package mypackage;

import javax.ws.rs.GET;
import javax.ws.rs.Path;
import javax.ws.rs.PathParam;
import javax.ws.rs.Produces;
import javax.ws.rs.Consumes;
import javax.ws.rs.core.MediaType;

@Path("/GetEDPInfo")
public class GetEDPInfo {

@GET
@Path("/{param}")
@Produces(MediaType.TEXT_PLAIN) @Consumes(MediaType.TEXT_PLAIN)
public String getMsg(@PathParam("param") String msg) {
String output = "Welcome"+ msg;
return output;
}

}

Answer 1

Change the <param-value>mypackage.GetEDPInfo</param-value> to following and it should work <param-value>mypackage</param-value>