I want to get all nonzeros from a row in a SparseTensor so "m" is the sparse tensor object that I have and row is a row I want to get all nonzeros values and indices from. So I want to return an array of the pair that is [(index, values)]. I hope I can get som help on the subject.
def nonzeros( m, row):
res = []
indices = m.indices
values = m.values
userindices = tf.where(tf.equal(indices[:,0], tf.constant(0, dtype=tf.int64)))
res = tf.map_fn(lambda index:(indices[index][1], values[index]), userindices)
return res
Error message in terminal
TypeError: Input 'strides' of 'StridedSlice' Op has type int32 that does not match type int64 of argument 'begin'.
EDIT: Input for nonzeros cm is a coo_matrix with values
m = tf.SparseTensor(indices=np.array([row,col]).T,
values=cm.data,
dense_shape=[10, 10])
nonzeros(m, 1)
if the data is
[[ 0. 1. 0. 0. 0. 0. 0. 0. 0. 1.]
[ 0. 0. 0. 0. 1. 0. 0. 0. 0. 2.]
[ 0. 0. 0. 1. 0. 0. 0. 0. 0. 0.]
[ 0. 0. 0. 0. 0. 0. 0. 0. 0. 1.]
[ 0. 0. 0. 0. 0. 0. 0. 0. 0. 0.]
[ 0. 0. 0. 0. 0. 0. 0. 0. 0. 0.]
[ 0. 0. 0. 0. 0. 0. 0. 0. 0. 0.]
[ 0. 0. 0. 0. 0. 0. 0. 0. 0. 0.]
[ 0. 0. 0. 0. 0. 0. 0. 0. 0. 0.]
[ 0. 0. 0. 0. 0. 0. 0. 0. 0. 1.]]
result should be
[index, value]
[4,1]
[9,2]
The problem is that index
inside the lambda is a Tensor and you can't use that directly to index into e.g. indices
. You could use tf.gather
instead. Also, you didn't make use of the row
parameter in the code you posted.
Try this instead:
import tensorflow as tf
import numpy as np
def nonzeros(m, row):
indices = m.indices
values = m.values
userindices = tf.where(tf.equal(indices[:, 0], row))
found_idx = tf.gather(indices, userindices)[:, 0, 1]
found_vals = tf.gather(values, userindices)[:, 0:1]
res = tf.concat(1, [tf.expand_dims(tf.cast(found_idx, tf.float64), -1), found_vals])
return res
data = np.array([[0., 1., 0., 0., 0., 0., 0., 0., 0., 1.],
[0., 0., 0., 0., 1., 0., 0., 0., 0., 2.]])
m = tf.SparseTensor(indices=np.array([[0, 1], [0, 9], [1, 4], [1, 9]]),
values=np.array([1.0, 1.0, 1.0, 2.0]),
shape=[2, 10])
with tf.Session() as sess:
result = nonzeros(m, 1)
print(sess.run(result))
which prints:
[[ 4. 1.]
[ 9. 2.]]