I wrote a Hanoi Tower program, but the output switches the A, B and C pillars because of the recursion. Is there a way to keep the pillars in order to make an animation? My code :
#include <iostream>
#include <vector>
#include <stdlib.h>
#include <windows.h>
using namespace std;
void printTowers(vector<int>& arr1, vector<int>& arr2, vector<int>& arr3)
{
printOut(arr1); //prints vector using iterator
printOut(arr2);
printOut(arr3);
}
//------------
// hanoi(number of disks, source pillar, spare pillar, target pillar)
void hanoi(int d, vector<int>& a, vector<int>& b, vector<int>& c)
{
if(d == 1)
{
c.push_back(a.back());
a.pop_back();
printTowers(a,b,c);
}
else{
hanoi(d-1,a,c,b);
hanoi(1,a,b,c);
hanoi(d-1,b,a,c);
}
}
//------------
int main()
{
int n = 3;
vector <int> A, B, C;
A.reserve(n); B.reserve(n); C.reserve(n);
for(int i=0; i<n; i++)
{
A.push_back(n-i);
}
hanoi(n,A,B,C);
return 0;
}
Sample output :
321 | 32 | 3 | | | 2 | | |
| | 1 | 3 | 21 | 3 | 1 | |
| 1 | 2 | 21 | 3 | 1 | 32 | 321|
Desired output :
321 | 32 | 3 | 3 | | 1 | 1 | |
| | 2 | 21 | 21 | 2 | | |
| 1 | 1 | | 3 | 3 | 32 | 321|
You can use an extra cell in your vector that tell you what pillar is it. For example
vector <int> A, B, C;
A.reserve(n+1); B.reserve(n+1); C.reserve(n+1);
A.push_back(-1);
B.push_back(-2);
C.push_back(-3);
Now
//add a new function to simplify code
void printTowerId(vector<int>& arr1, vector<int>& arr2, vector<int>& arr3, int id){
if(arr1[0] == id) printOut(arr1);
if(arr2[0] == id) printOut(arr2);
if(arr3[0] == id) printOut(arr3);
}
And your original function looks like
void printTowers(vector<int>& arr1, vector<int>& arr2, vector<int>& arr3)
{
printTowerId(arr1, arr2, arr3, -1);
printTowerId(arr1, arr2, arr3, -2);
printTowerId(arr1, arr2, arr3, -3);
}
Take care that in your recursion does not occupy the cell that you added