I need (if it is possible) to handle an "url" like this (in an email I need to open my app ("wics")):
http://wics/resetPassword/[email protected]/FOOBARTOKEN
I have this in my AndroidManifest.xml
<activity android:name=".ResetPasswordActivity">
android:label="@string/app_name">
<intent-filter>
<action android:name="android.intent.action.VIEW"/>
<category android:name="android.intent.category.DEFAULT"/>
<category android:name="android.intent.category.BROWSABLE" />
<data android:scheme="http"
android:host="wics"/>
</intent-filter>
</activity>
How can I get "[email protected]" and "FOOBARTOKEN" in my ResetPasswordActivity ?
I have insert this code:
Intent intent = getIntent();
Uri uri = (Uri)intent.getData();
But now ? split "uri" string and get 3td and 4th elements ?
Well you could do something like this.
<meta-data android:name="my_url" android:value="http://wics/resetPassword/[email protected]/FOOBARTOKEN" />
then get it in code.
ApplicationInfo appInfo = getPackageManager().getApplicationInfo(getPackageName(), PackageManager.GET_META_DATA);
Bundle bundle = appInfo.metaData;
String url = bundle.getString("my_url");
Uri uri = Uri.parse(url);
Then split on the "/" delimiter.
String[] arr = url.split("/");
then all you need to do is loop over the arr and find your words. make any sense?