How to access the ancestor of an object in python

Question

Suppose class A is inherited from B and B is inherited from C.

class C():
    def my_method(self):
        pass

class B(C):
    def my_method(self):
        pass

class A(B):
    def my_method(self):
        # Call my_method from B
        super(A, self).my_method()
        # How can I call my_method from C here ?

Question: How can I call my_method from C ?

Answer 1

You can call C's my_method() method simply by calling the "unbound" method directly, with self passed as an argument. For example:

class C(object):
    def my_method(self):
        print('C.my_method')

class B(C):
    def my_method(self):
        print('B.my_method')

class A(B):
    def my_method(self):
        print('A.my_method')
        super(A, self).my_method()  # calls B.my_method(self)
        C.my_method(self)           # calls C.my_method(self)

a = A()
a.my_method()

When run, that will print the following (note the (object) is required for super() to work on Python 2.x):

A.my_method
B.my_method
C.my_method

However, as others have pointed out, this may not be the best way to achieve what you want. Can you give a concrete example of what you're trying to achieve in context?