I am creating an app in which I let the user to share an audio file that is presen on the external storage.
I try to use this code but it is not working.
//This is getting the absolute path of the parent folder where the
//file is situated
File mFolder= new File(m_sdcard+m_confi);
// This take us to folder where the file is situated
File mAbFolder = new File(mFolder, "temp");
// Taking the files in an array
File[] mAllFiles= mAbFolder.listFiles();
//Getting the URI
Uri contentUri = FileProvider.getUriForFile(mContext, "com.androidpackagename.fileprovider", mImageFiles[1]);
Intent intent = new Intent(Intent.ACTION_SEND);
intent.setDataAndType(contentUri, mContext.getContentResolver().getType(contentUri));
intent.setFlags(Intent.FLAG_GRANT_READ_URI_PERMISSION);
mContext.startActivity(intent);
Now when I am running this code, it shows me the share menu. But when I click on any item such as Gmail, it put the uri into the "TO" field.
And I also tried to share it on Whatsapp. When I select a user to share this, nothing happens and I get back to my app.
My manifest is :
<?xml version="1.0" encoding="utf-8"?>
<manifest xmlns:android="http://schemas.android.com/apk/res/android"
package="com.androidpackagename">
<uses-permission android:name="android.permission.READ_EXTERNAL_STORAGE"/>
<uses-permission android:name="android.permission.WRITE_EXTERNAL_STORAGE"/>
<application
android:allowBackup="true"
android:icon="@mipmap/ic_launcher"
android:label="@string/app_name"
android:supportsRtl="true"
android:theme="@style/AppTheme">
<activity android:name=".MainActivity">
<intent-filter>
<action android:name="android.intent.action.MAIN" />
<category android:name="android.intent.category.LAUNCHER" />
</intent-filter>
</activity>
<provider
android:name="android.support.v4.content.FileProvider"
android:authorities="com.androidpackagename.fileprovider"
android:grantUriPermissions="true"
android:exported="false">
<meta-data
android:name="android.support.FILE_PROVIDER_PATHS"
android:resource="@xml/filepath" />
</provider>
</application>
</manifest>
My filepath xml is having
<external-path
name="external"
path="Android/data/com.androidpackagename/temp/" />
</paths>
Please help on this, thanks in advance.
I try to use this code but it is not working.
That is not how you use ACTION_SEND
. Quoting the documentation:
Input: getType() is the MIME type of the data being sent. get*Extra can have either a EXTRA_TEXT or EXTRA_STREAM field, containing the data to be sent. If using EXTRA_TEXT, the MIME type should be "text/plain"; otherwise it should be the MIME type of the data in EXTRA_STREAM.
So, replace:
Intent intent = new Intent(Intent.ACTION_SEND);
intent.setDataAndType(contentUri, mContext.getContentResolver().getType(contentUri));
with:
Intent intent = new Intent(Intent.ACTION_SEND);
intent.setType(mContext.getContentResolver().getType(contentUri));
intent.putExtra(Intent.EXTRA_STREAM, contentUri);
(though it would be much more efficient for you to just put in the MIME type directly in setType()
, rather than using getContentResolver().getType(contentUri)
, since hopefully you know what this file is and what its MIME type is)