Problem casting STL complex<double> to fftw_complex

Question

The FFTW manual says that its fftw_complex type is bit compatible to std::complex<double> class in STL. But that doesn't work for me:

#include <complex>
#include <fftw3.h>
int main()
{
   std::complex<double> x(1,0);
   fftw_complex fx;
   fx = reinterpret_cast<fftw_complex>(x);
}

This gives me an error:

error: invalid cast from type ‘std::complex<double>’ to type ‘double [2]’

What am I doing wrong?

Answer 1

Re-write your code as follows:

#include <complex>
#include <fftw3.h>
int main()
{
   std::complex<double> x(1,0);
   fftw_complex fx;
   memcpy( &fx, &x, sizeof( fftw_complex ) );
}

Every compiler I've used will optimise out the memcpy because it is copying a fixed, ie at compile time, amount of data.

This avoids pointer aliasing issues.

Edit: You can also avoid strict aliasing issues using a union as follows:

#include <complex>
#include <fftw3.h>
int main()
{
   union stdfftw
   {
       std::complex< double > stdc;
       fftw_complex           fftw;
   };
   std::complex<double> x(1,0);
   stdfftw u;
   u.stdc = x;
   fftw_complex fx = u.fftw;
}

Though strictly this C99 rules (Not sure about C++) are broken as reading from a different member of a union to the one written too is undefined. It works on most compilers though. Personally I prefer my original method.