initialize std::array without copying/moving elements

Question

#include <iostream>
#include <string>
#include <array>

class C {
private:
    std::string a;
    std::string b;
    std::string c;
public:
    C(std::string a_, std::string b_, std::string c_) : a{a_},b{b_},c{c_} {}
    ~C(){};
    C(const C&) =delete;
    C(const C&&) =delete;
    const C& operator=(const C&) =delete;
    const C& operator=(const C&&) =delete;
};

std::array<C,2> array = {C("","",""),C("","","")};

int main()
{}

this won't compile (Android Studio with NDK and clang) with a "call to deleted constructor of c" error. I know that I can e.g. use a std::vector and emplace_back() to construct an element directly inside the container, but in my code I want to only use fixed-sized containers and non-copyable/moveable objects for optimization. I'm probably missing sth basic here, but isn't there a way to initialize the std::array without first having to construct the individual elements and then copy them there?

Answer 1

You can use brace enclosed initializers instead of temporary c objects:

std::array<c,2> array = {{{"",""},{"",""}}};

or

std::array<c,2> array{{{"",""},{"",""}}};