Odd behaviour when comparing Java and Jython types

Question

Why do I experience the following behaviour when comparing a Java integer to a Python one of the same value in Jython?

>>> from java.lang import Integer
>>> 10 == Integer(10)
False
>>> 10 <= Integer(10)
True
>>> 10 >= Integer(10)
True

Okay, so I find it weird that both <= and >= operators evaluate as expected, yet == does not... So now lets check implicit conversions between Java & Jython types:

>>> i = Integer(10)
>>> i == 10
False

What about other Java classes I hear you say? Lets try:

>>> from java.lang import Boolean
>>> Boolean(0) == False
False
>>> Boolean(0) == True
False
>>> Boolean(0)  # lets just check it is a Java false not a Python one
false

Am I missing something or is it just as simple as the __eq__ magic (dunder) methods are broken for the Java classes (I am using Jython 2.7)?

EDIT

Thanks to weston for clarifying that in java 10 == new Integer(10) evaluates as true and therefore the question is not a duplicate of What is the difference between == vs equals() in Java?

Answer 1

Essentially it's because == compares references for boxed types, not the actual values.

But to muddy the waters further <= and >= will auto-unbox any boxed operands.