How do I print an array, pause it and continue to print the array in c++?

Question

How do I display 3 names at a time, pausing to let the user press a key before the list continues displaying.

My code now only loops the first 3 values of the array

#include <iostream> 
#include <string> 
#include <iomanip> 

using std::setw; 
using namespace std; 

int main() { 

    string a; 
    string names[10]; //size of array 

    for (int i = 0; i < 10; i++) 
    { 
        std::cout << "Enter name "; 
        std::cin >> a; //user input 

        names[i] = a; //assigns input to array 
    } 
    cout << "\n"; 

    for (int k = 0; k < 10; k++) 
    { 
        for (int j = 0; j < 3; j++) 
        { 
            cout << names[j] << endl; 
        } 

        system("pause"); 
    } 

}

Answer 1

I changed the answer based on your comment. Instead of sleeping we just pause and wait until user inputs anything into the keyboard. Also a note, since you're using namespace, you don't need to include std::, I decided to use it since I was unsure what way you wanted.

#include <iostream>
#include <string>
#include <iomanip>

using std::setw;
using namespace std;

int main() {

    string a;
    int pauseCheck = 0; //new var
    string names[10]; //size of array

    for (int i = 0; i < 10; i++) {
        std::cout << "Enter name ";
        std::cin >> a; //user input

        names[i] = a; //assigns input to array
    }
    cout << "\n";

    for (int k = 0; k < 10; k++) {

        cout << names[k] << endl;
        pauseCheck++; //increments check

        if (pauseCheck == 3) { //if equals 3
            system("pause"); //we pause till user input
            pauseCheck = 0; //reset pause check
        }
    }
    system("pause"); //last and final pause before program ends
}