What does a constructor function's __proto__ attribute point to?

Question

I'm trying to go back and get a better understanding of prototypal inheritance. I understand that an instance's __proto__ attribute points to the constructor function's prototype object, but what does the constructor function's __proto__ attribute point to?

I had assumed that as the constructor function was itself an instance of Function, that it would point to the Function constructor's prototype object, but the following shows it to be an empty function.

var Example = function(){
   this.attribute = 'example';
}

var exampleInstance = new Example();

exampleInstance.__proto__ === Example.prototype // true
Example.__proto__ // function() {}

[Edit] Ovidiu Dolha has now confirmed my understanding so maybe this will be helpful to somebody.

Answer 1

Example.__proto__ will be the same as Function.prototype, just as exampleInstance.__proto__ is the same as Example.prototype

This is because Example is an instance of a Function.

Everything will eventually get to Object.prototype which is the root in terms of prototypical inheritance.

Note that you should avoid using __proto__ if possible as it is considered deprecated. Instead use Object.getPrototypeOf()