why constructors are called if they are not inherited?

Question

the code is printing all the constructors. i read that constructors are not inherited when we derive a class from another class. then why creation of c is invoking constructors from b and a

class A
{
public:
  A()  { cout << "A's constructor called" << endl; }
};

class B
{
public:
  B()  { cout << "B's constructor called" << endl; }
};

class C: public B, public A  // Note the order
{
public:
  C()  { cout << "C's constructor called" << endl; }
};

int main()
{
    C c;
    return 0;
}

Answer 1

When the document you read said constructors are "not inherited", what it means is that if class A defines a constructor A::A(int x), then a child class B will not automatically have a constructor that takes an int.

However, it's still necessary to initialize the values of the parent class; otherwise, the parent object might be in an invalid state. Constructors are used to initialize classes, so means one of the parent class' constructors must be called from the child constructor's initializer list. If the parent class has a default constructor, that one gets called by default. That's what you see in your example. If the parent doesn't provide a default constructor, you have to specify which one you want called:

class A
{
public:
  A(int x)  { cout << "A's constructor called" << endl; }
};

class C: public A
{
public:
  C()  
  : A(7)  /* compilation will fail without this line */
  { cout << "C's constructor called" << endl; }
};