Java. Super call in class which extends Object

Question

I often see the code like this:

class MyClass{
      private int a;
      public MyClass(int a){
           super();        //what is the purpose of this method call?
           this.a = a;
      }
      //other class methods here
}

If class extends object, super() call invokes Object constructor which, as I know, does nothing. Then why it's needed to call super()? I'm interested in that particular case, when super() does nothing because it just calls Object().

Answer 1

First of all I recommend reading the source - documentation. Then a quote of jb-nizet's answer:

Note that this explicit call is unnecessary since the compiler would add it for you. You only need to add a super() call in a constructor when you want to invoke a superclass constructor with arguments.

In Java, super refers to the parent class. We can use it in two ways:

super() is calling the constructor of the parent class. super.toString() will call the parent class' implementation of toString method.

In your example:

class MyClass{
      private int a;
      public MyClass(int a){
           super();        //what purpose of this?
           this.a = a;
      }
      //other class methods here
}

it's calling the constructor of Object which is blank, so it's just being pedantic, but if we modify it:

class Foo extends Bar{
      private int a;
      public Foo(int a){
           super();        //what purpose of this?
           this.a = a;
      }
      //other class methods here
}

it stands for calling Bar's constructor first.

Another usage which I have earlier described is:

class Bar {
    public String toString() {
        return "bar";
    }
}

class Foo extends Bar{
      String foo = "foo";
      public Foo(){
           super();        //what purpose of this?
      }
      public String toString() {
          super.toString()
}

will result in returning "bar".