Scanner.hasNextLong Error

Question

Hello and thanks in advance,

I'm having a problem with the java.util.Scanner Here is my code:

public static void ScanInput(String Choice) {

    if(scanner.hasNextLong()){

        long input = scanner.nextLong();
        long length = String.valueOf(input).length();

        if(length <= 10){

            if(Choice == Choice1){

                Converter.Decimal(input);

            } else if(Choice == Choice2) {

                Converter.Binary(input);

            }
        } else {

            System.out.println(error);

            scanner.close();

            ScanInput(DecimalToBinary.choice);
        }


    } else {

        System.out.println(error);

        scanner.close();

        ScanInput(DecimalToBinary.choice);

    }

    scanner.close();
}

the use of this does not really matter. The problem is that when i enter an value bigger than 10 digits it crashes. So it seems that i used an int or so??

(Because of the maximum size of an int).

BUT I used long....

My debug instructor points at

if(scanner.hasNextLong()){

And that is also the place where things go to shit... Please help!

Answer 1

If the value is bigger than 9223372036854775807(MAX value for long) then use BigInteger, something like this:

if (scanner.hasNextBigInteger()) {
   BigInteger big = scanner.nextBigInteger();
}

Right now the compiler is treating your input as integer as apparently your long input doesn't have suffix L. In java long ends with L, e.g:

long lg = 24863512789L;

Fix this and it'll work fine.